Q1603 Design Parking System-简单

Design Parking System

Question

Design a parking system for a parking lot. The parking lot has three kinds of parking spaces: big, medium, and small, with a fixed number of slots for each size.

Implement the ParkingSystem class:

ParkingSystem(int big, int medium, int small) Initializes object of the ParkingSystem class. The number of slots for each parking space are given as part of the constructor. bool addCar(int carType) Checks whether there is a parking space of carType for the car that wants to get into the parking lot. carType can be of three kinds: big, medium, or small, which are represented by 1, 2, and 3 respectively. A car can only park in a parking space of its carType. If there is no space available, return false, else park the car in that size space and return true.

Constraints:

0 <= big, medium, small <= 1000 carType is 1, 2, or 3 At most 1000 calls will be made to addCar

Example 1:

Input ["ParkingSystem", "addCar", "addCar", "addCar", "addCar"] [[1, 1, 0], [1], [2], [3], [1]] Output [null, true, true, false, false]

Explanation ParkingSystem parkingSystem = new ParkingSystem(1, 1, 0); parkingSystem.addCar(1); // return true because there is 1 available slot for a big car parkingSystem.addCar(2); // return true because there is 1 available slot for a medium car parkingSystem.addCar(3); // return false because there is no available slot for a small car parkingSystem.addCar(1); // return false because there is no available slot for a big car. It is already occupied.

Approach 1: 直接处理

class ParkingSystem:
    carslots = [0] * 4
    def __init__(self, big: int, medium: int, small: int):
        self.carslots[1] = big
        self.carslots[2] = medium
        self.carslots[3] = small

    def addCar(self, carType: int) -> bool:
        if self.carslots[carType] > 0:
            self.carslots[carType] -= 1
            return True
        return False
# Your ParkingSystem object will be instantiated and called as such:
# obj = ParkingSystem(big, medium, small)
# param_1 = obj.addCar(carType)

复杂度分析

• 时间复杂度：

• 空间复杂度：